Sometimes you may need set time limit on function call or limit execution time on function call in Python. This is especially required if you have long running functions. In this article, we will learn how to set timeout on function call in Python.
How to Set Timeout on Function Call in Python
You can easily set timeout for python functions, using signal library. Here are the steps for the same.
1. Import Signal Module
The first step is to import signal module. This package is already installed by default in every Python version.
import signal
2. Create Signal Handler
Next, we define a signal handler function that is called when timeout occurs. In our case, we simply raise an exception and display a message.
def handler(signum, frame): print("Forever is over!") raise Exception("end of time")
3. Create long running function
Next, we define a long running function that runs forever. You can modify it as per your requirement.
def loop_forever(): import time while 1: print("sec") time.sleep(1)
4. Register Signal Function Handler
We register signal function handler with the following command.
signal.signal(signal.SIGALRM, handler)
The above line means that whenever signal.SIGALRM signal is triggered, handler function is called.
5. Define Timeout For Function
Next, we define a timeout of 10 seconds for function. This means that after 10 seconds signal.SIGALRM will be triggered.
signal.alarm(10)
6. Call Function
Finally, we call the long running function.
try: loop_forever() except Exception as exc: print(exc)
You will see the following output. If you get syntax error in above code, try using ‘except Exception, exc’ instead.
sec sec sec sec sec sec sec sec Forever is over! end of time
You will see that the function is stopped after 10 seconds and timeout message is displayed in the output.
Please note, the handler function is called 10 seconds after the signal.alarm(10) is called and not when the long running function is called. After timeout, it raises an exception that can be used in regular python code.
In this article, we have learnt how to set timeout on function in python. This is very useful to prevent long running functions from blocking your system resources and affecting performance.
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Unfortunately getting an error:
except Exception, exc:
^
SyntaxError: invalid syntax
Do you have an idea?
Ah, nowadays it should be:
except Exception as exc:
Thank you for pointing it out. We have updated the post accordingly.